1. A farmer borrowed ₹3600 at 15% simple interest per annum. At the end of 4 years, he cleared the account by paying ₹4000 and a cow. The cost of the cow is

  • ₹ 1000
  • ₹ 1200
  • ₹ 1550
  • ₹ 1760
Show Explanation
Correct Answer: ₹ 1760
S.I. = (3600 × 15 × 4)/100 = ₹ 2160
Total amount = 3600 + 2160 = ₹ 5760
Cost of cow = 5760 – 4000 = ₹ 1760

2. Ramakant invested amounts in two schemes A and B in the ratio 5:4 for 5 years. Scheme A offers 8% simple interest plus 20% bonus on interest. Scheme B offers 9% simple interest. If ₹20000 was invested in Scheme A, total maturity amount is

  • ₹ 50800
  • ₹ 51200
  • ₹ 52800
  • ₹ 58200
Show Explanation
Correct Answer: ₹ 52800
5x = 20000 ⇒ x = 4000
Scheme B investment = 4x = 16000
Interest in A = (20000 × 8 × 5)/100 = 8000
Bonus = 20% of 8000 = 1600
Total A interest = 9600
Interest in B = (16000 × 9 × 5)/100 = 7200
Total interest = 9600 + 7200 = 16800
Total maturity amount = 20000 + 16000 + 16800 = ₹ 52800

3. Simple interest on ₹500 for 4 years at 6.25% p.a. equals simple interest on ₹400 at 5% p.a. for how many years?

  • 4 years
  • 5 years
  • 6¼ years
  • 8⅔ years
Show Explanation
Correct Answer: 6¼ years
(500 × 6.25 × 4)/100 = (400 × 5 × T)/100
T = (500 × 6.25 × 4) / (400 × 5) = 6¼ years

4. A person invested some amount at 12% and some at 10% simple interest. Total yearly interest was ₹130. If interchanged, interest would be ₹134. Amount invested at 12% was

  • ₹ 400
  • ₹ 500
  • ₹ 700
  • ₹ 800
Show Explanation
Correct Answer: ₹ 500
12x + 10y = 13000
10x + 12y = 13400
Solving ⇒ x = ₹ 500

5. Two equal sums are lent at 8% and 7% p.a. The former is recovered 6 months earlier. Amount in each case is ₹2560. The sum and time are

  • ₹ 2000, 3.5 years × 4 years
  • ₹ 1500, 3.5 years × 4 years
  • ₹ 2000, 4 years × 5.5 years
  • ₹ 3000, 4 years × 4.5 years
Show Explanation
Correct Answer: ₹ 2000, 3.5 years × 4 years
Solving equations gives T = 4 years
Principal = ₹ 2000
Time = 3.5 years and 4 years

6. A man invested ₹5000 at R% and ₹4000 at (R+1)% simple interest. If interest after 4 years is same, R is

  • 4%
  • 5%
  • 6¼%
  • 8⅓%
Show Explanation
Correct Answer: 4%
5000R × 4 = 4000(R+1) × 4
Solving ⇒ R = 4%

7. A sum was put at simple interest for 3 years. If rate was 1% higher, it would fetch ₹5100 more. The sum is

  • ₹ 120000
  • ₹ 125000
  • ₹ 150000
  • ₹ 170000
Show Explanation
Correct Answer: ₹ 170000
3x/100 = 5100
x = ₹ 170000

8. A computer costs ₹39000 cash or ₹17000 down payment plus five monthly instalments of ₹4800. Rate of interest under instalment plan is

  • 35.71% p.a.
  • 36.71% p.a.
  • 37.71% p.a.
  • 38.71% p.a.
Show Explanation
Correct Answer: 38.71% p.a.
Balance = 39000 – 17000 = 22000
Using instalment S.I. equation:
22000 + 275R/3 = 24000 + 40R
Solving ⇒ R = 38.71% p.a.

9. Vishwas borrowed ₹30000, part at 12% and part at 10%. After 2 years, total paid ₹36480. Amount borrowed at 12% was

  • ₹ 12000
  • ₹ 16000
  • ₹ 17500
  • ₹ 18000
Show Explanation
Correct Answer: ₹ 12000
Total interest = 36480 – 30000 = 6480
Solving equation ⇒ x = ₹ 12000

10. A man divided his share between sons A and B such that interest of A at 15% for 3 years is double that of B at 12% for 5 years. Ratio of shares is

  • 2/3
  • 3/2
  • 3/8
  • 8/3
Show Explanation
Correct Answer: 8/3
(x × 15 × 3)/100 = 2(y × 12 × 5)/100
45x = 120y
x/y = 8/3