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11. A sum of ₹18750 is left by a father to be divided between his two sons aged 12 and 14 years, so that when they attain 18 years, the amounts received at 5% simple interest will be equal. The present shares are
For 12-year-old: Interest for 6 years.
For 14-year-old: Interest for 4 years.
x + (x × 5 × 6)/100 = (18750 − x) + ((18750 − x) × 5 × 4)/100
Solving ⇒ x = ₹9000
Other share = 18750 − 9000 = ₹9750
12. An amount of ₹1,00,000 is invested in two shares yielding 9% and 11% p.a. respectively. If the total annual interest is 9¾%, the investments were
9x/100 + 11(100000 − x)/100 = 9750
Solving ⇒ x = ₹62500
Other investment = ₹37500
13. A sum of ₹1440 is lent in three parts such that the interests on the first at 2% for 3 years, second at 3% for 4 years and third at 4% for 5 years are equal. The difference between the largest and smallest parts is
(x × 2 × 3)/100 = (y × 3 × 4)/100 = ([1440 − (x + y)] × 4 × 5)/100
Solving ⇒ First = ₹800, Second = ₹400, Third = ₹240
Required difference = 800 − 240 = ₹560
14. A man invested 1/3 of his capital at 7%, 1/4 at 8% and the remainder at 10%. If annual income is ₹561, the capital is
(x/3 × 7/100) + (x/4 × 8/100) + (5x/12 × 10/100) = 561
Solving ⇒ x = ₹6600
15. The sum invested in Scheme B is thrice that in Scheme A. Scheme A earns 8% p.a. for 4 years and Scheme B earns 13% p.a. for 2 years. Total interest earned is ₹1320. Amount invested in Scheme A was
(x × 4 × 8)/100 + (3x × 2 × 13)/100 = 1320
Solving ⇒ x = ₹1200
16. What would be the compound interest on ₹8400 @ 12.5% p.a. for 3 years?
C.I. = 11960.16 − 8400 = ₹ 3560.16
17. Compound interest on ₹2800 for 18 months at 10% p.a. is
Interest for 6 months = 154
C.I. = ₹ 434
18. Compound interest on ₹20480 at 6.25% for 2 years 73 days is
Interest for 73 days = 289
C.I. = ₹ 2929
19. Compound interest on ₹10000 at 4%, 5%, 6% for 3 years is
C.I. = ₹ 1575.20
20. Compound interest on ₹10000 @20% p.a. compounded half-yearly for 2 years is
C.I. = ₹ 4641
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