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1. A farmer borrowed ₹3600 at 15% simple interest per annum. At the end of 4 years, he cleared the account by paying ₹4000 and a cow. The cost of the cow is
- ₹ 1000
- ₹ 1200
- ₹ 1550
- ₹ 1760
Total amount = 3600 + 2160 = ₹ 5760
Cost of cow = 5760 – 4000 = ₹ 1760
2. Ramakant invested amounts in two schemes A and B in the ratio 5:4 for 5 years. Scheme A offers 8% simple interest plus 20% bonus on interest. Scheme B offers 9% simple interest. If ₹20000 was invested in Scheme A, total maturity amount is
- ₹ 50800
- ₹ 51200
- ₹ 52800
- ₹ 58200
Scheme B investment = 4x = 16000
Interest in A = (20000 × 8 × 5)/100 = 8000
Bonus = 20% of 8000 = 1600
Total A interest = 9600
Interest in B = (16000 × 9 × 5)/100 = 7200
Total interest = 9600 + 7200 = 16800
Total maturity amount = 20000 + 16000 + 16800 = ₹ 52800
3. Simple interest on ₹500 for 4 years at 6.25% p.a. equals simple interest on ₹400 at 5% p.a. for how many years?
- 4 years
- 5 years
- 6¼ years
- 8⅔ years
T = (500 × 6.25 × 4) / (400 × 5) = 6¼ years
4. A person invested some amount at 12% and some at 10% simple interest. Total yearly interest was ₹130. If interchanged, interest would be ₹134. Amount invested at 12% was
- ₹ 400
- ₹ 500
- ₹ 700
- ₹ 800
10x + 12y = 13400
Solving ⇒ x = ₹ 500
5. Two equal sums are lent at 8% and 7% p.a. The former is recovered 6 months earlier. Amount in each case is ₹2560. The sum and time are
- ₹ 2000, 3.5 years × 4 years
- ₹ 1500, 3.5 years × 4 years
- ₹ 2000, 4 years × 5.5 years
- ₹ 3000, 4 years × 4.5 years
Principal = ₹ 2000
Time = 3.5 years and 4 years
6. A man invested ₹5000 at R% and ₹4000 at (R+1)% simple interest. If interest after 4 years is same, R is
- 4%
- 5%
- 6¼%
- 8⅓%
Solving ⇒ R = 4%
7. A sum was put at simple interest for 3 years. If rate was 1% higher, it would fetch ₹5100 more. The sum is
- ₹ 120000
- ₹ 125000
- ₹ 150000
- ₹ 170000
x = ₹ 170000
8. A computer costs ₹39000 cash or ₹17000 down payment plus five monthly instalments of ₹4800. Rate of interest under instalment plan is
- 35.71% p.a.
- 36.71% p.a.
- 37.71% p.a.
- 38.71% p.a.
Using instalment S.I. equation:
22000 + 275R/3 = 24000 + 40R
Solving ⇒ R = 38.71% p.a.
9. Vishwas borrowed ₹30000, part at 12% and part at 10%. After 2 years, total paid ₹36480. Amount borrowed at 12% was
- ₹ 12000
- ₹ 16000
- ₹ 17500
- ₹ 18000
Solving equation ⇒ x = ₹ 12000
10. A man divided his share between sons A and B such that interest of A at 15% for 3 years is double that of B at 12% for 5 years. Ratio of shares is
- 2/3
- 3/2
- 3/8
- 8/3
45x = 120y
x/y = 8/3